Here’s a problem (2.1.4, p. 23) from Lang’s “A Second Course in Calculus”:
Find the velocity vector of the following curve: (cos(3t), sin(3t)).
Finding the velocity vector simply requires you to take the derivative of each term. Here’s a good chance to remember the chain rule:
Therefore, the velocity vector of (cos(3t), sin(3t)) is (-3sin(3t), 3cos(3t)).
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